更新时间2018-11-18 10:35:27
x²-x 3分之6x 1与-x² x-3分之4x-5通分
(6x+1)/(x²-x+3)+(4x-5)/(-x²+x-3)
=(6x+1)/(x²-x+3)-(4x-5)/(x²-x+3)
=[(6x+1)-(4x-5)]/(x²-x+3)
=(6x-4x+6)/(x²-x+3)
=2(x+3)/(x²-x+3)
望采纳哦
(6X+1)/(X^2-X+3)=(6X+1)/(X^2-X+3)
(4X-5)/(-X^2+X-3)=(5-4X)/(X^2-X+3)