更新时间2018-07-18 17:57:27
设x为正整数，且满足3^x+1·2^x-3^x·2^x+1=6^6,则x=______. ???
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3^(x+1)2^x-3^x2^(x+1)
=3*3^x*2^x-2*3^x*2^x
=3^x*2^x
=6^x
=6^6
x=6
3^(x+1)2^x-3^x2^(x+1)
=3*3^x*2^x-2*3^x*2^x
=3^x*2^x
=6^x
=6^6
x=6
3^(x+1)2^x-3^x2^(x+1)
=3*3^x*2^x-2*3^x*2^x
=3^x*2^x
=6^x
=6^6
所以x=6
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