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3a^2-[7a^2-2a-3(a^2-a)+1]先去括号,再合并同类项

更新时间2022-07-20 16:44:58

3a^2-[7a^2-2a-3(a^2-a)+1]

=3a^2-[7a^2-2a-3a^2+3a+1]

=3a^2-7a^2+2a+3a^2-3a-1

=-a^2-a-1


3a²-[7a²-2a-3(a²-a)+1]

=3a²-7a²+2a+3(a²-a)-1

=3a²-7a²+2a+3a²-3a-1

=(3a²-7a²+3a²)+(2a-3a)-1

=(3-7+3)a²+(2-3)a-1

=-a²-a-1

上一篇:2x^2-2y^2)-3(xy^3+x^2)+3(xy^3+y^2)其中x=-1,y=2化简求值

下一篇:设a,b,c是不为1的整数,(a,b,c)=1,且1/a+1/b=1/c,求证:a+b,a-c,b-c都是完全平方数。