对f（x）求导，附过程

更新时间2022-05-20 04:41:44

 

f(x)=x+2√(x²-3x+3)

f'(x)=[x+2√(x²-3x+3)]'

=x'+2[√(x²-3x+3)]'

=1+2(x²-3x+3)'/[2√(x²-3x+3)]

=1+(2x-3)/√(x²-3x+3)

用到的公式：

(x^n)'=nx^(n-1)

[f(u)]'=u'f'(u)