更新时间2019-07-12 01:22:13
①=9又4分之3+7又6分之5
=17又12分之7
②=1又6分之5-1又6分之5
=0
只看到一道,答案应该是17又12分之7!
先化假分数,然后再取最小公倍数。之后就是加减问题。61/4—11/2+47/6.最小公倍数是12.所以化为183/12—66/12+94/12.加减结果211/12。保留假分数或者带分数就是17又12分之7.第二题也是这样步骤。只要认真做一做就可以了,不难的
(15+1/4)-(5+1/2)+(7+5/6)
=(15+1/4)+[(7+5/6)-(5+1/2)]
=(15+1/4)+(2+1/3)
=(17+7/12)
(1+5/6)-[(3+1/3)-(1+1/2)]
=(1+1/3)+1/2-(3+1/3)+(1+1/2)
=[1/2+(1+1/2)]-[(3+1/3)-(1+1/3)]
=2-2
=0
你在为难我胖虎
解:
15+1/4-(5+1/2)+7+1/6
=15-5+7+(1/4-1/2+1/6)
=17+(3-6+2)/12
=17-1/12
=16又11/12
1+5/6-[3+1/3-(1+1/2)]
=1+5/6-(3+1/3-1-1/2)
=1+5/6-[2-(3-2)/6]
=1-2+5/6+1/6
=-1+1
=0
感觉是
第一题
原式=
15又1/4-5又2/4+7又5/6
=9又3/4+7又5/6
=9又9/12+7又10/12
=17又7/12
第二题
原式=
1又5/6-(3又2/6-1又3/6)
=1又5/6-1又5/6
=0