求教啊学霸
更新时间2019-01-22 10:53:18
解:
(1)
原式=【sin(360°-40°)-sin(180°+40°)-tan (360°+40°)】/【tan (360°-40°)+cos40°+cos(180°-40°)】
=【-sin40°+sin40°-tan 40°】/【-tan 40°+cos40°-cos40°】
=1
(2)
原式=2^2log(4)(1-lg3)+lg(3*10)
=4^log(4)(1-lg3)+lg3 +lg10
=1-lg3+lg3 +1
=0
O(∩_∩)O~