更新时间2018-08-23 12:04:34
解:根据题意
(x-3)/2+3≤x+1
x-3+6≤2x+2
x-2x≤2+3-6
-x≤-1
x≥1
(x-3)÷2+3≤x+1 则:x-3≤[(x+1)-3]×2 即:x-3≤2x-4 移项得:
4-3≤2x-x 即:1≤x
回答完毕保证正确
(x-3)/2+3≤x+1
x-3≤2x-4
x+1≤2x
x≥1
(x-3)/2+3=<x+1
x-3+6=<2x+2
x+3=<2x+2
x>=1
(x-3)/2+3≤x+1
(x-3)/2≤x+1-3=x-2
x-3≤2(x-2)=2x-4
x-2x≤-4+3
-x≤-1
x≥1
有2种情况:
情况1:
(x-3)/2+3≤x+1
(x-3)/2+3-3≤x+1-3
(x-3)/2≤x-2
(x-3)≤2(x-2)
x-3≤2x-4
x-3-2x+3≤2x-4-2x+3
-x≤-1
x≥1
情况2:
(x-3)/(2+3)≤x+1
(x-3)/5≤x+1
x-3≤5(x+1)
x-3≤5x+5
x-3-5x+3≤5x+5-5x+3
-4x≤8
4x≥-8
x≥-2
原式=(x-3)/2+3≤x+1→x-3+6≤2x+2→1≤x。