更新时间2018-08-19 11:35:13
7、∵ f(1) = a + b + c = 0,a > b > c, a = -( b + c ),∴ a > 0,b,c < 0;
y = a [ x^2 + (b/a)x + (b/(2a))^2 ] + c - b^2/(4a^2)
= a[ x + b/(2a) ]^2 + c - b^2/(4a^2)
∴ 对称轴为 -b/(2a),顶点 c - b^2/(4a^2) < 0;
另一个零点 ( x + 1 )/2 = -b/(2a),x = -b/a - 1;
∵ f(m) < 0,∴ -b/a - 1 < m < 1, -b/a + 2 < m + 3 < 4;
∴ f(m+3) > 0;
f(1/2) = a/4 + b/2 + c = -b/4 - c/4 + b/2 + c = b/4 + 3c/4 < 0;
∴ f(m+3) * f(1/2) < 0 。