更新时间2018-07-02 04:50:07
Sub zimu()
Randomize
Dim i As Integer
Do
i = Int(Rnd * 58 + 65)
Loop While i > 90 And i < 97
L.Caption = Chr(i)
L.Left = Rnd * (Me.ScaleWidth - L.Width)
L.Top = 0
End Sub
Private Sub Command1_Click()
zimu
L.Visible = True
Timer1.Interval = 200
End Sub
Private Sub Form_KeyPress(KeyAscii As Integer)
If L.Caption = Chr(KeyAscii) Then
zimu
End If
End Sub
Private Sub Timer1_Timer()
L.Top = L.Top + 100
If L.Top >= Me.ScaleHeight Then
L.Caption = zimu
End If
End Sub
说明:timer事件驱动的L.Caption = zimu这里总是提示错误,怎样解决?
你的
zimu()
是个过程,不是函数,它没有返回值,不能赋给别的变量的
L.Caption = zimu
肯定不对啊
直接改为zimu可以运行