偏微分怎么求啊谢谢

更新时间2018-05-06 16:12:12

z=f(x^2-y^2,  sin(xy))

∂z/∂x=f'(u)*2x+f'(v)*cos(xy)*y

∂z/∂y=f'(u)*2y+f'(v)*cos(xy)*x

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