更新时间2018-03-23 17:53:33
2^(4n+1)/[4^(2n)+16^n]
=2*2^(4n)/[2*4^(2n)]
=2^(4n)/2^(4n)
=1
(负27)的负15次方乘以(负9)的二十次方除以(负3)的负7次方
=(-3^-45)*3^40/(-3^7)
=3^(-45+40-7)
=3的负12次方
2^[4n+1]/(4^[2n+1】+16^n)
分母=2^[4n+2】+2^4n
2^(4n+1)/[4^(2n+1)+16^n]
=2^(4n)*2/[4^(2n)*4+16^n]
=16^n*2/(16^n*4+16^n)
=2*16^n/(5*16^n)
=2/5
2^(4n+1)/[4^(2n+1)+16^n]
=2*2^4n/[2^(4n+2)+2^2n]
=2*2^4n/2^4n(2^2+1)
=2/(2^2+1)
=2/5
答案应该是1~
2^(4n+1)/[4^(2n+1)+16^n]
=2^(4n+1)/【2^(2*(2n+1)+2^(4n)]
=2^4n*2/2^4n(2^2+1)
=2/5
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