更新时间2018-03-21 19:31:15
要过程,要明了,清晰
{(x+2)²+2(x+2)(x-2)-3(x+2)(x-3)}÷(x+2)
=(x+2){(x+2)+2(x-2)-3(x-3)}÷(x+2)
=x+2+2x-4-3x+9
=7
里面的项目都有x+2直接全部除以x+2
解:原式=x+2+2(x-2)-3(x-3)
=x+2+2x-4-3x+9
=7
前提是x≠-2
{(x+2)的平方+2(x+2)(x-2)-3(x+2)(x-3)}除以(x+2)
=(x+2)+2(x-2)-3(x-3)
=x+2+2x-4-3x+9
=7