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(1-4y)(1+4y)+(1+4y)^2,其中y=5分之2化简求值

更新时间2022-06-24 14:21:49

(1-4y)(1+4y)+(1+4y)²

=1-(4y²)+1+2(4y)+(4y)²

=2+8y

=2+8*2/5

=5.2

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2(3x+1)(1-3x)-(x-2)(2+x)

=2[1-(3x)²]-(x²-2²)

=2-18x²-x²+4

=6-19x²

=6-19*2²

=6-76

=-70

(1-4y)(1+4y)+(1+4y)^2

=1-16y^2+1+8y+16y^2

=2+8y

y=2/5

2+8*2/5

=52/5


2(3x+1)(1-3x)+(x-2)(2+x)

=2*(3x-9x^2+1-3x)+(2x+x^2-4-2x)

=2*(1-9x^2)+x^2-4

=2-18x^2+x^2-4

=-17x^2-2

x=2

-17*2^2-2

=-70

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